18x^2-109x+162=0

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Solution for 18x^2-109x+162=0 equation:



18x^2-109x+162=0
a = 18; b = -109; c = +162;
Δ = b2-4ac
Δ = -1092-4·18·162
Δ = 217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-109)-\sqrt{217}}{2*18}=\frac{109-\sqrt{217}}{36} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-109)+\sqrt{217}}{2*18}=\frac{109+\sqrt{217}}{36} $

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